Attacking RSA

Suppose Nikita's public key is $ (n,e)$ and her decryption key is $ d$ , so $ ed\equiv 1\pmod{\varphi (n)}$ . If somehow we compute the factorization $ n=pq$ , then we can compute $ \varphi (n)=(p-1)(q-1)$ and hence compute $ d$ . Thus if we can factor $ n$ then we can break the corresponding RSA public-key cryptosystem.



Subsections

William 2007-06-01