Suppose
is a prime such that
.
In what follows, we will be stating some standard facts
taken from [Maz78, §2(e)] (which in turn relies
on [DR73]).
Let
be the
minimal proper regular model for
over
,
and let
denote the relative dualizing sheaf of
over
(it is the sheaf of regular differentials as in [MR91, §7]).
The Tate curve over
gives rise to a morphism from
to
the smooth locus of
.
Since the module of completed Kahler
differentials for
over
is free of rank
on the basis
,
we obtain a map
$q$-exp
.
The natural morphism
identifies
with the identity
component of
(see, e.g., [BLR90, §9.4-9.5]).
Passing to tangent spaces along the identity section over
,
we obtain an isomorphism
.
Using Grothendieck duality, one gets
an isomorphism
, where
is the cotangent
space at the identity section. On the Néron model
,
the group of global differentials is the same as the group
of invariant differentials, which in turn is naturally
isomorphic to
. Thus we obtain
an isomorphism
.
Let
be a
-module equipped with an injection
of
-modules such that
is annihilated by
.
If
, assume moreover that
is a
-module and that the inclusion in the previous
sentence is a homomorphism of
-modules.
As a typical example,
,
with the injection
.
Let
be the composition of the inclusions
where the last inclusion follows from a ``local'' version of Theorem 3.4. The maps
where the map tex2html_wrap_inline$q$-exp is the tex2html_wrap_inline$q$-expansion map on differentials as in [Maz78, §2(e)] (actually, Mazur works over tex2html_wrap_inline$Z$; our map is obtained by tensoring with tex2html_wrap_inline$Z_(&ell#ell;)$).
We say that a subgroup
of an abelian
group
is saturated (in
)
if the quotient
is torsion free.
which is obtained by tensoring the inclusion
obtained by tensoring (1) with
First suppose that
does not divide
.
Then
is smooth and proper over
.
Thus the formation of
is compatible with any base change on
(such as reduction
modulo
).
The injectivity of
now follows since by hypothesis
the induced map
is injective, and
is injective by the
Next suppose that
divides
.
First we verify that
is stable under
.
Suppose
. Choose
such that the
image of
in
is
, and let
.
Because
in
, there
exists
such that
.
Let
; then
is actually in
(since
).
Now
is annihilated by every element of
, hence
so is
; thus
.
By hypothesis,
.
Then
Reducing modulo
Since
is an involution,
and by hypothesis either
is odd
or
is a scalar,
the space
breaks up into a direct sum of
eigenspaces under
with eigenvalues
.
It suffices to show that if
is an element of either
eigenspace, then
.
For this, we use a standard argument that goes back to Mazur
(see, e.g., the proof of Prop. 22 in [MR91]); we give
some details to clarify the argument in our situation.
Following the proof of Prop. 3.3 on p. 68 of [Maz77], we have
In the following, we shall think of
Suppose
is in the
eigenspace
(we will treat the cases of
and
eigenspaces together).
We will show that
is trivial
over
, the
base change of
to an algebraic closure
,
which suffices for our purposes.
Since
, we have
,
and so the special fiber
is
as depicted on p. 177 of [Maz77]:
it consists of the
union of two copies of
identified transversely
at the supersingular points, and some copies of
, each of which
intersects exactly one
of the two copies of
and perhaps another
,
all of them transversally.
All the singular
points are ordinary double points, and the cusp
lies on
one of the two copies of
.
In particular,
is locally
a complete intersection, hence Gorenstein,
and so by [DR73, § I.2.2, p. 162], the sheaf
is invertible.
Since
,
the differential
vanishes on the
copy of
containing the
cusp
by the
-expansion principle (which is easy in this case,
since all that is being invoked here is
that on an integral curve,
the natural map from the group of global sections of
an invertible sheaf into the completion of the sheaf's
stalk at a point is injective).
The two copies of
are swapped under
the action of the Atkin-Lehner involution
, and thus
vanishes on the other copy that does
not contain the cusp
. Since
, we see that
is zero on both copies of
.
Also, by the description of the relative dualizing sheaf
in [DR73, § I.2.3, p. 162], if
is a normalization, then
correponds
to a meromorphic differential
on
which
is regular outside the inverse images (under
)
of the double points on
and has at worst a simple pole at any point that lies over
a double point on
. Moreover, on the
inverse image of any double point on
,
the residues of
add to zero.
For any of the
's, above a point of intersection
of the
with a copy of
,
the residue of
on the inverse image of
the copy of
is zero (since
is
trivial on both copies of
), and thus
the residue of
on the inverse image of
is zero.
Thus
restricted to
the inverse image of
is regular away from
the inverse image of any point where the
meets another
(recall that there can be at most one such point).
Hence
the restriction of
to the inverse image of the
is either regular everywhere or is regular away from one point where
it has at most a simple pole; in the latter case, the residue is zero
by the residue theorem. Thus in either case,
restricted to the inverse image of the
is regular, and therefore is zero.
Thus
is trivial on all the copies of
as well.
Hence
, as was to be shown.
William Stein 2006-06-25