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Mordell's Theorem



Venerable Problem: Find an algorithm that, given an elliptic curve $ E$ over  $ \mathbb{Q}$, outputs a complete description of the set of rational points $ (x_0, y_0)$ on $ E$.


This problem is difficult. In fact, so far it has stumped everyone! There is a conjectural algorithm, but nobody has succeeded in proving that it is really an algorithm, in the sense that it terminates for any input curve $ E$. Several of your profs at Harvard, including Barry Mazur, myself, and Christophe Cornut (who will teach Math 129 next semester) have spent, or might spend, a huge chunk of their life thinking about this problem.

How could one possible ``describe'' the group $ E(\mathbb{Q})$, since it can be infinite? In 1923, Mordell proved that there is always a reasonable way to describe $ E(\mathbb{Q})$.

Theorem 5.1 (Mordell)   The group $ E(\mathbb{Q})$ is finitely generated.

This means that there are points $ P_1,\ldots, P_s \in E(\mathbb{Q})$ such that every element of $ E(\mathbb{Q})$ is of the form $ n_1 P_1 + \cdots + n_s P_s
$ for some $ n_1, \ldots n_s\in\mathbb{Z}$. I will not prove Mordell's theorem in this course, but see §1.3 of [Kato et al.].

Example 5.2   Consider the elliptic curve $ E$ given by $ y^2 = x^3 -6x - 4$. Then $ E(\mathbb{Q})\approx (\mathbb{Z}/2\mathbb{Z})\times \mathbb{Z}$ with generators $ (-2,0)$ and $ (-1,1)$. We have

$\displaystyle 5(-1,1) = \left(-\frac{131432401}{121462441} , -\frac{1481891884199}{1338637562261}\right).$

Trying finding that point without knowing about the group law!


next up previous
Next: About this document ... Up: Lecture 26: The Elliptic Previous: An Example Over a
William A Stein 2001-11-16