Extensions of the Argument

The method of proof of this section generalizes to show that the continued fraction expansion of $ e^{1/n}$ is

$\displaystyle [1, (n-1), 1, 1, (3n-1), 1, 1, (5n-1), 1, 1, (7n-1),\ldots]
$

for all $ n\in\mathbb{N}$ (see Exercise 5.6).



William 2007-06-01