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Lecture 34: The Birch and Swinnerton-Dyer Conjecture, Part 1

William Stein


Date: Math 124 $ \quad$ HARVARD UNIVERSITY $ \quad$ Fall 2001

The next three lectures will be about the Birch and Swinnerton-Dyer conjecture, which is considered by many people to be the most important accessible open problem in number theory. Today I will guide you through Wiles's Clay Math Institute paper on the Birch and Swinnerton-Dyer conjecture.

On Friday, I will talk about the following open problem, which is a frustrating specific case of the Birch and Swinnerton-Dyer conjecture. Let $ E$ be the elliptic curve defined by

$\displaystyle y^2 + xy = x^3 - x^2 -79x + 289.
$

Denote by $ L(E,s)=\sum_{n=1}^{\infty} a_n n^{-s}$ the corresponding $ L$-series, which extends to a function everywhere. The graph of $ L(E,s)$ for $ s\in (0,5)$ is given on the next page. It can be proved that $ E(\mathbb{Q}) \approx \mathbb{Z}^4$ by showing that

$\displaystyle (8,7),\ \left(\frac{120}{27},\frac{29}{27}\right),\,
\left(\frac{70}{8},\frac{81}{8}\right),\,$    and $\displaystyle \left(\frac{564}{8}, \frac{665}{64}\right)
$

generate a ``subgroup of finite index'' in $ E(\mathbb{Q})$. The Birch and Swinnerton-Dyer Conjecture then predicts that

$\displaystyle \ord_{s=1}L(E,s)=4,$

which looks plausible from the shape of the graph on the next page. It is relatively easy to prove that the following is equivalent to showing that $ \ord_{s=1}L(E,s)=4$:



Open Problem: Prove that $ L''(E,1) = 0$.

If you could solve this open problem, people like Gross, Tate, Mazur, Zagier, Wiles, me, etc., would be very excited. The related problem of giving an example of an $ L$-series with $ \ord_{s=1}L(E,s)=3$, was solved as a consequence of a very deep theorem of Gross and Zagier, and resulting in an effective solution to Gauss's class number problem.

John Tate gave a talk about the BSD conjecture for the Clay Math Institute. I strongly encourage you to watch it online at

http://www.msri.org/publications/ln/hosted/cmi/2000/cmiparis/index-tate.html




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William A Stein 2001-12-05